3m^2-48m+45=0

Solution for 3m^2-48m+45=0 equation:

3m^2-48m+45=0

a = 3; b = -48; c = +45;
Δ = b2-4ac
Δ = -482-4·3·45
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-42}{2*3}=\frac{6}{6}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+42}{2*3}=\frac{90}{6}
=15
$